Usando bucles, escriba un programa que encuentre el número primo más grande menor que 10,000

import math
def maxPrimeFactor(n):
   # number must be even
   while n % 2 == 0:
      max_Prime = 2
      n /= 1
   # number must be odd
   for i in range(3, int(math.sqrt(n)) + 1, 2):
      while n % i == 0:
         max_Prime = i
         n = n / i
   # prime number greator than two
   if n > 2:
      max_Prime = n
   return int(max_Prime)

# Driver code to test above function
n = 10000
print(maxPrimeFactor(n))