# Assume the availability of a function named printStars that can be passed a non-negative integer n and print a line of asterisks. Write a function named printTriangle that receives a non-negative integer n and prints a triangle of asterisks as follows: first a line of 1 asterisk, followed by a line of 2 asterisks, and then a line of 3 asterisks, and so on and finally a line of n asterisks. For example, if the function received 5 it would print: * * * * * * * * * * * * * * * The function must not use a loop of any kind (for, while, do-while) to accomplish its job. The function should invoke printStars to accomplish the task of printing a single line.

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### CHALLENGE:

Assume the availability of a function named printStars that can be passed a non-negative integer n and print a line of asterisks. Write a function named printTriangle that receives a non-negative integer n and prints a triangle of asterisks as follows: first a line of 1 asterisk, followed by a line of 2 asterisks, and then a line of 3 asterisks, and so on and finally a line of n asterisks. For example, if the function received 5 it would print: * * * * * * * * * * * * * * * The function must not use a loop of any kind (for, while, do-while) to accomplish its job. The function should invoke printStars to accomplish the task of printing a single line.

### SOLUTION:

```

void printTriangle(int n){
if(n <= 0) return;
printStars(n);
cout<<endl;
printTriangle(n-1);
}

```

• Kenneth Tuten says:

fixed:

void printTriangle(int n)
{
if(n <= 0) return;
printStars(n);cout<<endl;
printTriangle(n-1);
}

• Kenneth Tuten says:

fixed:

void printTriangle(int n)
{
if(n <= 0) return;
printStars(n);cout<<endl;
printTriangle(n-1);
}

EDIT: Sorry, this was for a variation of the problem posted here. Your code is correct

• Anon says:

WRONG! You’re printing the stars in reverse order (e.x. 5 to 1). Pay attention! It wants 1 to 5 instead.

• Maurice says:

void printTriangle(int n){
if(n==0) return;

printTriangle(n-1);

printStars(n);
}

• Rohan says:

This works ….

• Zack Withers says:

• Gee says: