Tag: 21210

Consider a simple form of integer division: m / k where we are guaranteed that m>=0 and k>0. This can be computed as follows: The quotient is 0 when k is greater than m. Otherwise, the quotient is one more than (m-k)/k . Write an int method named quotient that accepts two int parameters, m and k, and recursively calculates and returns the integer quotient of m/k. You can count on m>=0 and k>0. Do not use a division operator here!

June 1, 2014 Matthew Maennche Java, Learn To Code 21210, Java
Consider a simple form of integer division: m / k where we are guaranteed that m>=0 and k>0. This can be computed as follows: The quotient is 0 when k is greater than m. Otherwise, the quotient is one more than (m-k)/k . Write an int method named quotient that accepts two int parameters, m and k, and recursively calculates and returns the integer quotient of m/k. You can count on m>=0 and k>0. Do not use a division operator here!

LANGUAGE: JAVA CHALLENGE: Consider a simple form of integer division: m / k where we are guaranteed that m>=0 and k>0. This can be computed as follows: The quotient is 0 when k is greater than m. Otherwise, the quotient is one more than (m-k)/k . Write an int method named quotient that accepts two int […]

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