LANGUAGE: JAVA
CHALLENGE:
Write a static method, getBigWords, that gets a single String parameter and returns an array whose elements are the words in the parameter that contain more than 5 letters. (A word is defined as a contiguous sequence of letters.)
EXAMPLE: So, if the String argument passed to the method was “There are 87,000,000 people in Canada”, getBigWords would return an array of two elements , “people” and “Canada”.
ANOTHER EXAMPLE: If the String argument passed to the method was “Send the request to support@turingscraft.com”, getBigWords would return an array of three elements , “request”, “support” and “turingscraft”.
SOLUTION:
public static String[] getBigWords(String sentence) {
sentence = sentence.replace('@', ' ');
sentence = sentence.replace('.', ' ');
sentence = sentence.replaceAll("\\d+.", "");
String[] tokens = sentence.split(" ");
StringBuilder sb = new StringBuilder();
for (String string : tokens) {
if (string.length() > 5) {
sb.append(string).append(" ");
}
}
return sb.toString().split(" ");
}
Use this:
public static String[] getBigWords(String str) {
str = str.replace(“@”, ” “);
str = str.replace(“.”, ” “);
str = str.replace(“,”, “”);
str = str.replace(“\\d+”, “”);
String[] myArr = str.split(” “);
java.util.ArrayList al = new java.util.ArrayList ();
for (int i = 0; i < myArr.length; i++) {
boolean notLetter = false;
for (int j = 0; j 5) {
al.add(myArr[i]);
}
}
String[] arr = al.toArray(new String[0]);
return arr;
}
this workspublic static String[] getBigWords(String sentence)
{
int totalbigWords, currentWordStart, currentWordEnd, pointer;
totalbigWords = currentWordStart = currentWordEnd = pointer = 0;
while ((pointer != sentence.length() – 1) && (!sentence.isEmpty()))
{
if(Character.isLetter(sentence.charAt(pointer)))
{
currentWordStart = pointer;
while ((Character.isLetter(sentence.charAt(pointer))) && (pointer 5)
{
totalbigWords++;
currentWordStart = currentWordEnd = pointer;
}
}
else pointer++;
} String[] bigWords = new String[totalbigWords];
totalbigWords = currentWordStart = currentWordEnd = pointer = 0;
while (pointer < sentence.length() – 1)
{
if(Character.isLetter(sentence.charAt(pointer)))
{
currentWordStart = pointer;
while ((Character.isLetter(sentence.charAt(pointer))) && (pointer 5)
{
bigWords[totalbigWords] = sentence.substring(currentWordStart, currentWordEnd);
totalbigWords++;
currentWordStart = currentWordEnd = pointer;
}
}
else pointer++;
}
return bigWords;
}