The ‘parseInt’ method of the ‘Integer’ class throws a ‘NumberFormatException’ when it is passed a String argument that it cannot convert to an int. Given the String variable s (which has already been assigned a value), write the code needed to convert the value in s assigning the result to the integer variable i

The ‘parseInt’ method of the ‘Integer’ class throws a ‘NumberFormatException’ when it is passed a String argument that it cannot convert to an int. Given the String variable s (which has already been assigned a value), write the code needed to convert the value in s assigning the result to the integer variable i

LANGUAGE: JAVA

CHALLENGE:

The ‘parseInt’ method of the ‘Integer’ class throws a ‘NumberFormatException’ when it is passed a String argument that it cannot convert to an int. Given the String variable s (which has already been assigned a value), write the code needed to convert the value in s assigning the result to the integer variable i

If a NumberFormatException is thrown, i should be assigned the value -1.

This content requires that you purchase additional access. The price is $2.99 or free for our Make Life Easier and 30 Days – Not Recurring members.

Purchase this Content ($2.99) Choose a Membership Level