The ‘parseInt’ method of the ‘Integer’ class throws a ‘NumberFormatException’ when it is passed a String argument that it cannot convert to an int. Given the String variable s (which has already been assigned a value), write the code needed to convert the value in s assigning the result to the integer variable i

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The ‘parseInt’ method of the ‘Integer’ class throws a ‘NumberFormatException’ when it is passed a String argument that it cannot convert to an int. Given the String variable s (which has already been assigned a value), write the code needed to convert the value in s assigning the result to the integer variable i

LANGUAGE: JAVA

CHALLENGE:

The ‘parseInt’ method of the ‘Integer’ class throws a ‘NumberFormatException’ when it is passed a String argument that it cannot convert to an int. Given the String variable s (which has already been assigned a value), write the code needed to convert the value in s assigning the result to the integer variable i

If a NumberFormatException is thrown, i should be assigned the value -1.

SOLUTION:

try {
    i = Integer.parseInt(s);
} 
catch (NumberFormatException e)  
{ 
    i = -1;
}

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