# Consider this data sequence: “3 11 5 5 5 2 4 6 6 7 3 -8”. Any value that is the same as the immediately preceding value is considered a CONSECUTIVE DUPLICATE. In this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6.

LANGUAGE: JAVA

CHALLENGE:
Consider this data sequence: “3 11 5 5 5 2 4 6 6 7 3 -8”. Any value that is the same as the immediately preceding value is considered a CONSECUTIVE DUPLICATE. In this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. Note that the last 3 is not a consecutive duplicate because it was preceded by a 7. Write some code that uses a loop to read such a sequence of non-negative integers , terminated by a negative number. When the code finishes executing, the number of consecutive duplicates encountered is printed. In this case,3 would be printed.

ASSUME the availability of a variable , stdin, that references a Scanner object associated with standard input.

### SOLUTION:

LANGUAGE: JAVA

CHALLENGE:
Consider this data sequence: “3 11 5 5 5 2 4 6 6 7 3 -8”. Any value that is the same as the immediately preceding value is considered a CONSECUTIVE DUPLICATE. In this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. Note that the last 3 is not a consecutive duplicate because it was preceded by a 7. Write some code that uses a loop to read such a sequence of non-negative integers , terminated by a negative number. When the code finishes executing, the number of consecutive duplicates encountered is printed. In this case,3 would be printed.

ASSUME the availability of a variable , stdin, that references a Scanner object associated with standard input.

SOLUTION:

```int firstNumber, secondNumber, duplicates;
secondNumber = duplicates = 0;
firstNumber = stdin.nextInt();
while (stdin.hasNextInt() && firstNumber > -1 && secondNumber > -1)
{
secondNumber = stdin.nextInt();
if (firstNumber == secondNumber)
{
duplicates++;
}
firstNumber = secondNumber;
}
System.out.println(duplicates);
```