### Language: Java

### Challenge:

The “odd/even factorial” of a positive integer n is represented as n and is defined non-recursively as: (n)(n-2)(n-4)…(4)(2) if n is even and is (n)(n-2)(n-4)…(5)(3) (1) if n is odd. For example 7 equals 7*5*3*1 or 105 and 6 equals 6*4*2 or 48. Come up with a recursive definition for n and use it to guide you to write a method definition for a method called oddevenfact that recursively calculates the odd/even factorial value of its single int parameter. The value returned by oddevenfact is a long..

### Solution:

long oddevenfact(int x){ if (x>2) return(oddevenfact(x-2) * (long) x); else return((long) x); }

I had this solution wrong