Write the definition of a method dashedLine, with one parameter, an int . If the parameter is negative or zero, the method does nothing. Otherwise it prints a complete line terminated by a newline to standard output consisting of dashes (hyphens) with the parameter’s value determining the number of dashes. The method returns nothing.
LANGUAGE: JAVA
CHALLENGE:
Write the definition of a method dashedLine, with one parameter, an int .
If the parameter is negative or zero, the method does nothing. Otherwise it prints a complete line terminated by a newline to standard output consisting of dashes (hyphens) with the parameter’s value determining the number of dashes. The method returns nothing.
SOLUTION:
The Bad News: The content you are trying to access is only available to members.
The Good News: You too can be a member, simply Click Here.
Already a member? Log In Here
Posted in Java, Learn To Code
7 Comments
Leave a Comment
You must be logged in to post a comment.
public static void dashedLine(int x)
{
if (x > 0)
{
while(x!=0)
{
System.out.print(“-“);
x–;
}
System.out.println(“\n”);
}
}
Just for posterity, this actually gives me a correct answer, as single characters generally use a single quote in the System.out.print class:
public static void dashedLine(int x)
{
if (x > 0)
{
while(x!=0)
{
System.out.print(‘-‘);
x–;
}
System.out.println(‘\n’);
}
}
public static void dashedLine(int a){
if(a>0){
for(int b=0; b < a; b++){
System.out.print("-");
}
System.out.println("\n");
}
}
public static void dashedLine(int x)
{
if (x > 0)
{
while(x!=0)
{
System.out.print(“-“);
x –;
}
System.out.println(“\n”);
}
}
public void dashedLine (int a)
{
if (a>0)
{
int i;
for (i=1;i<=a;i=i+1)
{
System.out.print("-");
}
System.out.println("");
}
}
public static void dashedLine(int x)
{
if (x > 0)
{
while(x!=0)
{
System.out.print(“-“);
x–;
}
System.out.println(“”);
}
}
void dashedLine(int p){
if (p>0){
for(int i=0;i<p;i++){
cout<<"-";
}
cout << endl;}
}