Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive. After the loop terminates , it prints out the sum of all the even integers read and the sum of all the odd integers read. Declare any variables that are needed.

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Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive. After the loop terminates , it prints out the sum of all the even integers read and the sum of all the odd integers read. Declare any variables that are needed.

LANGUAGE: C++

CHALLENGE:

Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive. After the loop terminates , it prints out the sum of all the even integers read and the sum of all the odd integers read. Declare any variables that are needed.

SOLUTION:


int odd=0;
int even=0;
int i=1;

while (i>0){
    	cin >> i;
    	if ((i % 2)==0 && (i>0)){
        	even+=i;
    	}

	if ((i % 2)!=0 && (i>0)){
        	odd+=i;
	}
}
cout << even << " " << odd;

4 comments

  • Ryan.Limanne says:

    If this program does not work, try replacing:
    cout << even << " " << odd;
    with
    cout << even << "" << endl;

  • Malcolm A. Morgan says:

    THIS IS THE CODE FOR C:

    int even=0;
    int i=1;

    while (i>0){
    scanf(“%d”,&i);
    if ((i % 2)==0 && (i>0)){
    even+=i;
    }

    }
    printf(“%d”,even);

  • matt says:

    int num = 1;
    int sumE = 0;
    int sumO = 0;
    int sumECounter = 0;
    int sumOCounter = 0;

    while (num > 0){
    cin >> num;
    if ((num%2 == 0) && (num>0)){
    sumE += num;
    sumECounter++;
    }
    if ((num%2 != 0) && (num>0)){
    sumO += num;
    sumOCounter++;
    }
    }
    cout << sumE << " " << sumO << " " << sumECounter << " " << sumOCounter << endl;

  • TheGreatest says:

    This works ladies…

    int odd=0;
    int even=0;
    int sumOdd=0;
    int sumEven = 0;
    int i=1;

    while (i>0){
    cin >> i;
    if ((i % 2)==0 && (i>0)){
    sumEven += i;
    even++;
    }

    if ((i % 2)!=0 && (i>0)){
    sumOdd += i;
    odd++;
    }
    }
    cout << sumEven << " " << sumOdd << " " << even << " " << odd;

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