LANGUAGE: C++
CHALLENGE:
Write a for loop that prints in ascending order all the positive multiples of 5 that are less than 175, separated by spaces.
SOLUTION:
for (int i=1; i<175; i++){
if ((i % 5) == 0){
cout << i << " ";
}
}
Write a for loop that prints in ascending order all the positive multiples of 5 that are less than 175, separated by spaces.
2 comments
Add comment
You must be logged in to post a comment.
THIS IS THE CODE FOR C:
int i;
for (i=1; i<175; i++){
if ((i % 5) == 0){
printf(" %d", i);
}
}
int i;
for ( i = 5; i<175; i+=5)
{
System.out.print(i + " ");
}